I HAVE to agree with alan cause one we disscussed this in class today and for ex. I take a right triangle the sides are 2-3-4 double the current perimeter 2+3+4=9x2=18=perimeter now current area=3x2=6/2=3 area now=6x4=24/2=12 4x3=12 so the area is right too
I am the mathematics teacher for the Specialized High School section at IP Kids Our goal this summer is to familiarize the students with the type of questions that will be given on the New York City Specialized High School Test. The test will be given on the first weekend in November 2009.
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8 comments:
the new perimeter will be doulbed of the original one and the new area will be four times the original one.(from Alan)
I HAVE to agree with alan cause one we disscussed this in class today and for ex.
I take a right triangle the sides are 2-3-4 double the current perimeter 2+3+4=9x2=18=perimeter now current area=3x2=6/2=3
area now=6x4=24/2=12
4x3=12 so the area is right too
The perimeter will be doubled and the area will be 4 x the amount of the old 1. we talked about it in class.
3 4 5 triangle
P = B + H + L
3 + 4 + 5 = 12
6 + 8 + 10= 24
A = B x H/2
3 x 4 = 12
6 x 8 = 48
The new perimeter will be double the original..... and the area will be multiplied by four. We did this in class ^_^
Excellent work. I am glad we were able to prove what Xiao Wei stated in his original comment.
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